add notes on thermal expansion, thermal conductivity

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Akbar Rahman 2021-12-21 20:25:57 +00:00
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@ -631,3 +631,143 @@ bonds between the surface of the fibre and matrix.
Kevlar/Epoxy | 1200 | 20 Kevlar/Epoxy | 1200 | 20
(All units in MPa) (All units in MPa)
# Thermal Properties of Materials
## Specific Heat Capacity
How much heat energy is required to raise the temperature of a body by one unit:
$$ C_p = \frac{\Delta E}{m\Delta T} $$
where $c$ is specific heat capacity.
It is measured at a constant pressure, usually $1.013\times 10^5$ Pa.
## Molar Heat Capacity
$$C_pm = \frac{\Delta E}{n\Delta T}$$
<details>
<summary>
#### What is a mole?
</summary>
> The mole (symbol: mol) is the base unit of amount of substance in the International System of
> Units (SI).
> It is defined as exactly $6.02214076\times 10^{23}$ elementary entities ("particles")
~ [Wikipedia: Mole (unit)](https://en.wikipedia.org/wiki/Mole_(unit))
<details>
<details>
<summary>
#### How Much Does a mol of Something weigh?
</summary>
A mol of an element weighs its relative atomic mass ($A_r$) but in grams.
For example, Carbon-12 has an $A_r$ of 12 (as it's made of 6 neutrons, 6 protons, and 6 electrons
which have negligible mass) so a mol of Carbon-12 has a mass of 12 g.
</details>
## Thermal Expansion
<details>
<summary>
### Origin of Thermal Expansion
</summary>
All atomic bonds vibrate, on the magnitude of gigahertz.
The bonds vibrate about a mean positoin and the vibration is a simple harmonic motion.
From the graph below you can see that as energy (in the form of heat) is supplied to the bonds,
the amplitude of the vibrations get larger and larger.
You can also see the mean position of the bond gets further and further away, meaning the volume
of the material also is increasing.
The mean position of the bond is what dictates the volume, as this means the inter-atomic
separation increases.
![Morse Potential Graph](./images/vimscrot-2021-12-21T19:51:58,667328620+00:00.png)
Morse potential is the energy well between 2 bonded atoms.
The graph is asymmetric due to the repulsion experienced by atoms as they apporach.
</details>
### Linear Coefficient of Thermal Expansion
$$\alpha_L = \frac{\Delta L}{L_0 \Delta T}$$
where $L$ is the sample length.
<details>
<summary>
#### Example 1
A 1 m long bar of aluminium metal cools in the solid state from 660 \textdegree{}C to
25 \textdegree{}C.
Calculate the length of the bar after it cools down, given $\alpha_L = 25\times10^{-6}$ K$^{-1}$.
</summary>
\begin{align*}
l_0 &= 1 \\
\Delta T &= T_f - T_0 = 25 - 660 = -635 \\
\\
\alpha_L &= \frac{l_f - l_0}{l_0 \Delta T} \\
\alpha_L l_0 \Delta T &= l_f - l_0 \\
l_f &= \alpha_L l_0 \Delta T + l_0 = 0.984
\end{align*}
</details>
### Linear Thermal Expansion and Isotropism
Since isotropic solids have the same properties in all directions, you can say that for an
isotropic solid:
$$\alpha_V = 3\alpha_L = \frac{\Delta V}{V_0 \Delta T}$$
### Reasons to Care About Thermal Expansion
- A coating on a material may fail if the thermal expansion coefficients do not match
- A brittle material may thermally shock and fracture due to thermal expansion mismatch between
the ouside and inside, especially if the material is not very thermally conductive
## Thermal Conductivity
Thermal conductivity is the rate at which heat power is transferred through a material.
$$\frac{Q}{A} = k \frac{\Delta T}{\Delta x}$$
where $Q$ is heat power, $A$ is area of the surface, $\frac{\Delta T}{\Delta x}$ is the
temperature gradient, and $k$ is the thermal conductivity constant.
<details>
<summary>
### Origin of Thermal Conductivity
</summary>
Heat is transferred through materials by electrons (and partially by atomic vibrations)
Metals have high thermal conductivity as their delocalised 'sea' electrons are about to move about
easily.
This makes them excellent conductors of heat and electricity.
Ceramics, glasses, and polymers do not have delocalised electrons and are therefore poor conductors
of heat and electricity (they are insulators).
Polymer foams are even better insulators because they have holes which lowers their density.
</details>