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@@ -547,3 +547,90 @@ $$Q = m (c_v-c_v)(T_2-T_1) = 0 $$
This proves that the isentropic version of the process adiabatic (no heat is transferred across the
boundary).
# 2nd Law of Thermodynamics
The 2nd Law recognises that processes happen in a certain direction.
It was discovered through the study of heat engines (ones that produce mechanical work from heat).
> Heat does not spontaneously flow from a cooler to a hotter body.
~ Clausius' Statement on the 2nd Law of Thermodynamics
> It is impossible to construct a heat engine that will operate in a cycle and take heat from a
> reservoir and produce an equivalent amount of work.
~ Kelvin-Planck Statement of 2nd Law of Thermodynamics
## Heat Engines
A heat engine must have:
- Thermal energy reservoir --- a large body of heat that does not change in temperature
- Heat source --- a reservoir that supplies heat to the engine
- Heat sink --- a reservoir that absorbs heat rejected from a heat engine (this is usually
surrounding environment)
![](./images/vimscrot-2022-03-22T09:17:36,214723827+00:00.png)
#### Steam Power Plant
![](./images/vimscrot-2022-03-22T09:19:07,697440371+00:00.png)
## Thermal Efficiency
For heat engines, $Q_{out} > 0$ so $W_{out} < Q_{in}$ as $W_{out} = Q_{in} - Q_{out}$
$$\eta = \frac{W_{out}}{Q_{in}} = 1 - \frac{Q_{out}}{Q_{in}}$$
Early steam engines had efficiency around 10% but large diesel engines nowadays have efficiencies
up to around 50%, with petrol engines around 30%.
The most efficient heat engines we have are large gas-steam power plants, at around 60%.
## Carnot Efficiency
The maximum efficiency for a heat engine that operates reversibly between the heat source and heat
sink is known as the *Carnot Efficiency*:
$$\eta_{carnot} = 1 - \frac{T_2}{T_1}$$
where $T$ is in Kelvin (or any unit of absolute temperature, I suppose)
Therefore to maximise potential efficiency, you want to maximise input heat temperature, and
minimise output heat temperature.
The efficiency of any heat engine will be less than $\eta_{carnot}$ if it operates between more than
two reservoirs.
## Reversible and Irreversible Processes
### Reversible Processes
A reversible process operate at thermal and physical equilibrium.
There is no degradation in the quality of energy.
There must be no mechanical friction, fluid friction, or electrical resistance.
Heat transfers must be across a very small temperature difference.
All expansions must be controlled.
### Irreversible Processes
In irreversible processes, the quality of the energy degrades.
For example, mechanical energy degrades into heat by friction and heat energy degrades into lower
quality heat (a lower temperature), including by mixing of fluids.
Thermal resistance at both hot sources and cold sinks are an irreversibility and reduce efficiency.
There may also be uncontrolled expansions or sudden changes in pressure.
# Energy Quality
## Quantifying Disorder (Entropy)
$$S = k\log_eW$$
where $S$ is entropy, $k = 1.38\times10^{-23}$ J/K is Boltzmann's constant, and $W$ is the number of
ways of reorganising energy.s