add uncommitted year 1 content
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@@ -547,3 +547,90 @@ $$Q = m (c_v-c_v)(T_2-T_1) = 0 $$
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This proves that the isentropic version of the process adiabatic (no heat is transferred across the
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boundary).
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# 2nd Law of Thermodynamics
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The 2nd Law recognises that processes happen in a certain direction.
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It was discovered through the study of heat engines (ones that produce mechanical work from heat).
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> Heat does not spontaneously flow from a cooler to a hotter body.
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~ Clausius' Statement on the 2nd Law of Thermodynamics
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> It is impossible to construct a heat engine that will operate in a cycle and take heat from a
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> reservoir and produce an equivalent amount of work.
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~ Kelvin-Planck Statement of 2nd Law of Thermodynamics
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## Heat Engines
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A heat engine must have:
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- Thermal energy reservoir --- a large body of heat that does not change in temperature
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- Heat source --- a reservoir that supplies heat to the engine
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- Heat sink --- a reservoir that absorbs heat rejected from a heat engine (this is usually
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surrounding environment)
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#### Steam Power Plant
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## Thermal Efficiency
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For heat engines, $Q_{out} > 0$ so $W_{out} < Q_{in}$ as $W_{out} = Q_{in} - Q_{out}$
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$$\eta = \frac{W_{out}}{Q_{in}} = 1 - \frac{Q_{out}}{Q_{in}}$$
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Early steam engines had efficiency around 10% but large diesel engines nowadays have efficiencies
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up to around 50%, with petrol engines around 30%.
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The most efficient heat engines we have are large gas-steam power plants, at around 60%.
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## Carnot Efficiency
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The maximum efficiency for a heat engine that operates reversibly between the heat source and heat
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sink is known as the *Carnot Efficiency*:
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$$\eta_{carnot} = 1 - \frac{T_2}{T_1}$$
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where $T$ is in Kelvin (or any unit of absolute temperature, I suppose)
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Therefore to maximise potential efficiency, you want to maximise input heat temperature, and
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minimise output heat temperature.
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The efficiency of any heat engine will be less than $\eta_{carnot}$ if it operates between more than
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two reservoirs.
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## Reversible and Irreversible Processes
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### Reversible Processes
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A reversible process operate at thermal and physical equilibrium.
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There is no degradation in the quality of energy.
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There must be no mechanical friction, fluid friction, or electrical resistance.
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Heat transfers must be across a very small temperature difference.
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All expansions must be controlled.
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### Irreversible Processes
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In irreversible processes, the quality of the energy degrades.
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For example, mechanical energy degrades into heat by friction and heat energy degrades into lower
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quality heat (a lower temperature), including by mixing of fluids.
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Thermal resistance at both hot sources and cold sinks are an irreversibility and reduce efficiency.
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There may also be uncontrolled expansions or sudden changes in pressure.
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# Energy Quality
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## Quantifying Disorder (Entropy)
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$$S = k\log_eW$$
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where $S$ is entropy, $k = 1.38\times10^{-23}$ J/K is Boltzmann's constant, and $W$ is the number of
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ways of reorganising energy.s
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