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---
author: Akbar Rahman
date: \today
title: MMME2053 // Elastic Instability (Buckling)
tags: [ elastic_instability, buckling ]
uuid: b8b2cff7-8106-4968-bab5-f4cffcf8b5a0
lecture_slides: [ ./lecture_slides/MMME2053-EI L1 Slides.pdf, ./lecture_slides/MMME2053-EI L2 Slides.pdf ]
lecture_notes: [ ./lecture_notes/Elastic Instability (Buckling) Notes.pdf ]
exercise_sheets: [ ./exercise_sheets/Elastic Instability (Buckling) Exercise Sheet.pdf, ./exercise_sheets/Elastic Instability (Buckling) Exercise Sheet Solutions.pdf ]
worked_examples: [ ./worked_examples/MMME2053-EI WE1 Slides.pdf ]
---
# Notes from Lecture Slides (2)
> In contrast to the classical cases considered here, actual compression members are seldom truly pinned or
> completely fixed against rotation at the ends. Because of this uncertainty regarding the fixity of the ends,
> struts or columns are often assumed to be pin-ended. This procedure is conservative.
>
> The above equations are not applicable in the inelastic range, i.e. for $\sigma > \sigma_y$ , and must be modified.
>
> The critical load formulae for struts or columns are remarkable in that they do not contain any strength
> property of the material and yet they determine the load carrying capacity of the member. The only material
> property required is the elastic modulus, $E$, which is a measure of the stiffness of the strut.
# Stability of Equilibrium
![(a) is a stable equilibrium (it will return to equilibrium if it deviates) whereas (b) is an unstable equilibrium (it will not return to equilibrium if it deviates)](./images/stable_unstable_equilibria.png)
# Critical Buckling Load on a Strut
Critical buckling load is given by:
$$P_c = \frac{\pi^2EI}{L_\text{eff}^2}$$
where $L_\text{eff}$ is the effective length:
- Free-fixed -> $L_\text{eff} = 2l$
- Hinged-hinged -> $L_\text{eff} = l$
- Fixed-hinged -> $L_\text{eff} = 0.7l$
- fixed-fixed -> $L_\text{eff} = 0.5l$
where $l = 0.5L$
Derivations detailed in lecture slides (1, pp. 8-21).
# Compression of Rods/Columns
Derivations detailed in lecture slides (2, pp. 3-5).
Buckling will occur if
$$\sigma = \frac{\pi^2E}{\frac{L^2}{K^2}}$$
where $k$ is the radius of gyration and $\frac{L}{K}$ is the slenderness ratio.
Plastic collapse will occur if $\sigma = \sigma_y$.
This can be represented diagrammatically:
![](./images/bucking_vs_plastic_collapse.png)

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---
author: Akbar Rahman
date: \today
title: MMME2053 // Thick Walled Cylinders
tags: [ thick_walled_cylinders ]
uuid: b53973dc-2c57-4e37-8409-96875125f4de
lecture_slides: [ ./lecture_slides/MMME2053_TC1_Intro.pdf, ./lecture_slides/MMME2053_TC2.pdf, ./lecture_slides/MMME2053_TC3.pdf ]
lecture_notes: [ ./lecture_notes/MMME2053_TC_Notes.pdf ]
exercise_sheets: [ ./exercise_sheets/Thick Cylinders Exercise Sheet.pdf, ./exercise_sheets/Thick Walled Cylinders Exercise Sheet Solutions.pdf ]
worked_examples: [ ./worked_examples/MMME2053_TC_WE1.pdf, ./worked_examples/MMME2053_TC_WE2.pdf, ./worked_examples/MMME2053_TC_WE3.pdf ]
---
# Lame's Equations
Derivation in lecture slides 2 (pp. 3-11)
$$\sigma_h = A + \frac{B}{r^2}$$
$$\sigma_r = A - \frac{B}{r^2}$$
where $A$ and $B$ are *Lame's constants* (constants of integration).
Note that $\sigma_r$ does not vary with radius, $r$.
## Obtaining Lame's Constants
The constants can be obtained by using the boundary conditions of the problem:
At the inner radius ($r = R_i$) the pressure is only opposing the fluid inside:
$$\sigma_r= -p_i$$
At the outer radius ($r = R_o$) the pressure is only opposing the fluid outside (e.g. atmospheric
pressure):
$$\sigma_r = -p_o$$
Therefore:
\begin{align*}
-p_i &= C - \frac{D}{R_i^2}
-p_o &= C - \frac{D}{R_o^2}
\end{align*}
where $C$ and $D$ are constants which can be determined.
## Cylinder with Closed Ends
$$\sigma_z = \frac{R_i^2p_i - R_o^2p_o}{R_o^2-R_i^2}$$
## Cylinder with Pistons
No axial load is transferred to the cylinder.
$$\sigma_z = 0$$
## Solid Cylinder
$$\sigma_r = \sigma_\theta = A$$