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@ -4,28 +4,12 @@ date: \today
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title: MMME2044 // Bearings
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tags: [ bearings ]
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uuid: 94cac3fd-c352-4fdd-833d-6129cb484b8a
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lecture_slides: [ ./lecture_slides/Lecture 7 - Bearings 1 – Plain Hydrodynamic Bearings 1.pdf, ./lecture_slides/Lecture 11 - Bearings 2 - Rolling Element Bearings.pdf ]
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lecture_slides: [ ./lecture_slides/Lecture 7 - Bearings 1 – Plain Hydrodynamic Bearings 1.pdf ]
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anki_deck_tags: [ bearings ]
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---
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> I don't think I ever finished these notes.
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# Errata
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## Lecture Slides 2 (Lecture 11), slide 18
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Static load carrying capacity equation is
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$$S_0 = \frac{P_0}{C_0}$$
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but should be:
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$$S_0 = \frac{C_0}{P_0}$$
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If the load applied to a bearing is half of its rated capacity,
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then you have a safety factor of 2.
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Therefore the equation in the slides must be incorrect.
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# Types of Bearings
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<details>
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uni/mmme/2047_thermodynamics_and_fluid_dynamics/exam_papers/2019-2020/MMME2047-2019-2020.pdf
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uni/mmme/2047_thermodynamics_and_fluid_dynamics/exam_papers/2019-2020/MMME2047-2019-2020.pdf
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@ -72,12 +72,11 @@ Nusselt number is a dimensionless number:
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$$\text{Nu} = \frac{hL}{k_f}$$
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where $k_f$ is conductivity of the fluid, $L$ is the representative length (e.g. diameter, length,
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internal width, etc.), and $h$ is heat transfer coefficient.
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internal width, etc.).
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Since $h$ is unknown a lot of the time, sometimes Nusselt number must be found through approximating
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by other dimensionless numbers: Prandtl, Reynolds, and Grashof.
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Nusselt number for a laminar forced flow is around 3.66.
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For a turbulent forced flow it is estimated to be:
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