Compare commits
4 Commits
fb21e1012f
...
d505de5ac1
Author | SHA1 | Date | |
---|---|---|---|
d505de5ac1 | |||
868fac25cf | |||
c90147635a | |||
c0c565a104 |
@ -4,12 +4,28 @@ date: \today
|
||||
title: MMME2044 // Bearings
|
||||
tags: [ bearings ]
|
||||
uuid: 94cac3fd-c352-4fdd-833d-6129cb484b8a
|
||||
lecture_slides: [ ./lecture_slides/Lecture 7 - Bearings 1 – Plain Hydrodynamic Bearings 1.pdf ]
|
||||
lecture_slides: [ ./lecture_slides/Lecture 7 - Bearings 1 – Plain Hydrodynamic Bearings 1.pdf, ./lecture_slides/Lecture 11 - Bearings 2 - Rolling Element Bearings.pdf ]
|
||||
anki_deck_tags: [ bearings ]
|
||||
---
|
||||
|
||||
> I don't think I ever finished these notes.
|
||||
|
||||
# Errata
|
||||
|
||||
## Lecture Slides 2 (Lecture 11), slide 18
|
||||
|
||||
Static load carrying capacity equation is
|
||||
|
||||
$$S_0 = \frac{P_0}{C_0}$$
|
||||
|
||||
but should be:
|
||||
|
||||
$$S_0 = \frac{C_0}{P_0}$$
|
||||
|
||||
If the load applied to a bearing is half of its rated capacity,
|
||||
then you have a safety factor of 2.
|
||||
Therefore the equation in the slides must be incorrect.
|
||||
|
||||
# Types of Bearings
|
||||
|
||||
<details>
|
||||
|
0
uni/mmme/2047_thermodynamics_and_fluid_dynamics/exam_papers/2019-2020/MMME2047-2019-2020.pdf
Executable file → Normal file
0
uni/mmme/2047_thermodynamics_and_fluid_dynamics/exam_papers/2019-2020/MMME2047-2019-2020.pdf
Executable file → Normal file
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
@ -72,11 +72,12 @@ Nusselt number is a dimensionless number:
|
||||
$$\text{Nu} = \frac{hL}{k_f}$$
|
||||
|
||||
where $k_f$ is conductivity of the fluid, $L$ is the representative length (e.g. diameter, length,
|
||||
internal width, etc.).
|
||||
internal width, etc.), and $h$ is heat transfer coefficient.
|
||||
|
||||
Since $h$ is unknown a lot of the time, sometimes Nusselt number must be found through approximating
|
||||
by other dimensionless numbers: Prandtl, Reynolds, and Grashof.
|
||||
|
||||
|
||||
Nusselt number for a laminar forced flow is around 3.66.
|
||||
For a turbulent forced flow it is estimated to be:
|
||||
|
||||
|
Binary file not shown.
Binary file not shown.
Binary file not shown.
Binary file not shown.
Loading…
Reference in New Issue
Block a user