fix typo in ac_power.md
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@ -26,9 +26,9 @@ $$P = \sqrt{3} V_lI_l\cos\gamma$$
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- For loads, this means that the voltage across them are the same, apart from the phase angles:
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\begin{align*}
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v_{1N} = V\cos{2\pi ft} \\
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v_{2N} = V\cos{2\pi ft - \frac{2\pi}{3} \\
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v_{3N} = V\cos{2\pi ft + \frac{2\pi}{3}
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v_{1N} = V\cos{2\pi ft} \\
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v_{2N} = V\cos{2\pi ft - \frac{2\pi}{3}} \\
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v_{3N} = V\cos{2\pi ft + \frac{2\pi}{3}}
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\end{align*}
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- Balanced loads and sources ensure that line/phase currents have equal magnitudes and that the
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