Material toughness
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@ -5,6 +5,8 @@ title: MMME1029 // Materials
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tags: [ uni, nottingham, mechanical, engineering, mmme1029, materials ]
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tags: [ uni, nottingham, mechanical, engineering, mmme1029, materials ]
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---
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---
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\tableofcontents
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# Lecture 1 (2021-10-04)
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# Lecture 1 (2021-10-04)
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## 1A Reading Notes
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## 1A Reading Notes
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@ -387,3 +389,129 @@ There are two ways to make polymers:
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- [Addition Poymerisation](http://www.chemguide.co.uk/14to16/organic/addpolymers.html)
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- [Addition Poymerisation](http://www.chemguide.co.uk/14to16/organic/addpolymers.html)
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- [Condensation Polymerisation](https://www.chemguide.uk/14to16/organic/condpolymers.html)
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- [Condensation Polymerisation](https://www.chemguide.uk/14to16/organic/condpolymers.html)
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# Elastic Deformaion
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Elastic deformation is deformation where the material will return to original shape after the
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applied stresses are removed.
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Elastic deformation is the first type of deformation that happens when stresses are applied to
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a material and is represented by the straight line at the beginning of a stress-strain curve.
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## Modulus of Resillience ($E_r$)
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This is the area under the elastic portion of a stress-strain graph of a material.
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# Plastic Deformation
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## Toughness (Absorbing Energy Through Plastic Deformation)
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- The toughness of a material is its ability to absorb energy through plastic deformation
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without fracturing
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- The material toughness of a ductile material can be determined by finding the area under its
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stress-strain curve (e.g. by integrating the graph)
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- Brittle materials like ceramics and glasses exhibit no material toughness
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- Ductile materials have a possibility of achieving large material toughness
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Ductility measures how much something deforms plastically before fracture, but just because a
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material is ductile does not make it tough.
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*The key to high material toughness is a good combination of large ultimate fracture stress and
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large ductility*.
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- The unit of toughness is energy per unit volume as toughness can be mathematically expressed as:
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$$toughness = \int^{\varepsilon_f}_0\! \sigma \,\mathrm{d}\varepsilon
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= \frac{\text{Energy}}{\text{Volume}} $$
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- A metal may have satisfactory toughness under static loads but fail under dynamic loads or impact
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This may be caused by the fact that ductility and toughness usually decrease as rate of loading
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increases.
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- Ductility and toughness decreasee with temperature
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- Notches in the material affect the distribution of stress in the material, potentially changing
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it from a uniaxial stress to multiaxial stress
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### Charpy Impact Test
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Measures material toughness by determining the amount of energy absorbed during fracture.
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It works by essentially dropping a hammer into a sample whose dimensions are standardized
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(usually either by BSI or ISO) and measuring how high the hammer goes up on the other side,
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after it breaks the material
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The height of the hammer after impact will tell you how much enery is left in it, and therefore
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how much has been aborbed by the now broken sample.
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Under a microscope, more ductile fractures appear fibrous or dull, whereas less ductile surfaces
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have granular or shiny surface texture.A
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The charpy test has a couple issues:
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- Results are prone to scatter as it is difficult to achieve a perfectly shaped notch
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- Temperature has to be strictly controlled since it affects a material's ductility
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#### The setup of a charpy impact test
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1. Sample is made to standardized dimensions, with a notch
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2. Sample is placed on support
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3. A very heavy hammer pendulum of mass $m$ is dropped from rest at $h_0$ to swing about a pivot,
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reaching $E_{kmax}$ vertically below the pivot.
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4.
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a. If no sample is in place then the hammer will swing back up on the other side to a height of
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$h_h$ where theoretically $h_h = h_0$
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b. With a sample placed vertically below, some of the $E_k$ is transferred to the sample to bend
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and (usually) break the sample.
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If breaks the sample, it will swing up to the other side, where its max height, $h_f$ can be
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used to calculate how much energy was used to break the sample:
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$$E = mg(h_h-h_f)$$
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Where $g$ is acceleration due to gravity.
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# Ductility
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Ductility is the plastic deformation a material withstands before fracture.
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# Griffith Surface Flaws
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These flaws vary in size and shape.
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They limit the ability of any material, brittle or ductile, to withstand tensile stresses as they
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concentrate the tensile forces applied to a smaller area.
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The stress at the tip of the flaw:
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$$\sigma_{actual} = 2\sigma\sqrt{\frac a r}$$
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For deep ($a$ is large) or thin ($r$ is small) the stress is magnified and, if it exceeds the UFS
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in a brittle material, the flaw will grow into a crack, resulting in the brittle material
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fracturing.
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However in a ductile material, the tip of the flaw can heal, reducing $a$ and increasing $r$.
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This is due to the chemical structure of ductile materials like metals.
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![](./images/vimscrot-2021-11-08T13:51:17,152036728+00:00.png)
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## Stress Intensity Factor
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Stress Intesity Factor, $K$:
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$$K = f\sigma\sqrt{\pi a}$$
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where:
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- $f$ is the geometry factor (1 would represent an infinite width sample, and 0 a 0 width sample)
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- $\sigma$ is applied tensile strength
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- $a$ is flaw depth
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## Fracture Toughness
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![An example sample for testing fracture toughenss. From: <https://www.researchgate.net/figure/Compact-tension-sample-geometry-used-for-fracture-toughness-measurement_fig2_340037774> [accessed 8 Nov, 2021]](./images/Compact-tension-sample-geometry-used-for-fracture-toughness-measurement.png)
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The value of $K$ that causes the notch to grow and cause fractures.
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This is value is known as the fracture toughness, $K_c$.
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At low thicknesses fracture toughness depends on thickness but as thickness increases, $K_c$
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decreases to the constant value, the plane strain fracture toughness, $K_{1c}$.
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