Material toughness

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@ -5,6 +5,8 @@ title: MMME1029 // Materials
tags: [ uni, nottingham, mechanical, engineering, mmme1029, materials ]
---
\tableofcontents
# Lecture 1 (2021-10-04)
## 1A Reading Notes
@ -387,3 +389,129 @@ There are two ways to make polymers:
- [Addition Poymerisation](http://www.chemguide.co.uk/14to16/organic/addpolymers.html)
- [Condensation Polymerisation](https://www.chemguide.uk/14to16/organic/condpolymers.html)
# Elastic Deformaion
Elastic deformation is deformation where the material will return to original shape after the
applied stresses are removed.
Elastic deformation is the first type of deformation that happens when stresses are applied to
a material and is represented by the straight line at the beginning of a stress-strain curve.
## Modulus of Resillience ($E_r$)
This is the area under the elastic portion of a stress-strain graph of a material.
# Plastic Deformation
## Toughness (Absorbing Energy Through Plastic Deformation)
- The toughness of a material is its ability to absorb energy through plastic deformation
without fracturing
- The material toughness of a ductile material can be determined by finding the area under its
stress-strain curve (e.g. by integrating the graph)
- Brittle materials like ceramics and glasses exhibit no material toughness
- Ductile materials have a possibility of achieving large material toughness
Ductility measures how much something deforms plastically before fracture, but just because a
material is ductile does not make it tough.
*The key to high material toughness is a good combination of large ultimate fracture stress and
large ductility*.
- The unit of toughness is energy per unit volume as toughness can be mathematically expressed as:
$$toughness = \int^{\varepsilon_f}_0\! \sigma \,\mathrm{d}\varepsilon
= \frac{\text{Energy}}{\text{Volume}} $$
- A metal may have satisfactory toughness under static loads but fail under dynamic loads or impact
This may be caused by the fact that ductility and toughness usually decrease as rate of loading
increases.
- Ductility and toughness decreasee with temperature
- Notches in the material affect the distribution of stress in the material, potentially changing
it from a uniaxial stress to multiaxial stress
### Charpy Impact Test
Measures material toughness by determining the amount of energy absorbed during fracture.
It works by essentially dropping a hammer into a sample whose dimensions are standardized
(usually either by BSI or ISO) and measuring how high the hammer goes up on the other side,
after it breaks the material
The height of the hammer after impact will tell you how much enery is left in it, and therefore
how much has been aborbed by the now broken sample.
Under a microscope, more ductile fractures appear fibrous or dull, whereas less ductile surfaces
have granular or shiny surface texture.A
The charpy test has a couple issues:
- Results are prone to scatter as it is difficult to achieve a perfectly shaped notch
- Temperature has to be strictly controlled since it affects a material's ductility
#### The setup of a charpy impact test
1. Sample is made to standardized dimensions, with a notch
2. Sample is placed on support
3. A very heavy hammer pendulum of mass $m$ is dropped from rest at $h_0$ to swing about a pivot,
reaching $E_{kmax}$ vertically below the pivot.
4.
a. If no sample is in place then the hammer will swing back up on the other side to a height of
$h_h$ where theoretically $h_h = h_0$
b. With a sample placed vertically below, some of the $E_k$ is transferred to the sample to bend
and (usually) break the sample.
If breaks the sample, it will swing up to the other side, where its max height, $h_f$ can be
used to calculate how much energy was used to break the sample:
$$E = mg(h_h-h_f)$$
Where $g$ is acceleration due to gravity.
# Ductility
Ductility is the plastic deformation a material withstands before fracture.
# Griffith Surface Flaws
These flaws vary in size and shape.
They limit the ability of any material, brittle or ductile, to withstand tensile stresses as they
concentrate the tensile forces applied to a smaller area.
The stress at the tip of the flaw:
$$\sigma_{actual} = 2\sigma\sqrt{\frac a r}$$
For deep ($a$ is large) or thin ($r$ is small) the stress is magnified and, if it exceeds the UFS
in a brittle material, the flaw will grow into a crack, resulting in the brittle material
fracturing.
However in a ductile material, the tip of the flaw can heal, reducing $a$ and increasing $r$.
This is due to the chemical structure of ductile materials like metals.
![](./images/vimscrot-2021-11-08T13:51:17,152036728+00:00.png)
## Stress Intensity Factor
Stress Intesity Factor, $K$:
$$K = f\sigma\sqrt{\pi a}$$
where:
- $f$ is the geometry factor (1 would represent an infinite width sample, and 0 a 0 width sample)
- $\sigma$ is applied tensile strength
- $a$ is flaw depth
## Fracture Toughness
![An example sample for testing fracture toughenss. From: <https://www.researchgate.net/figure/Compact-tension-sample-geometry-used-for-fracture-toughness-measurement_fig2_340037774> [accessed 8 Nov, 2021]](./images/Compact-tension-sample-geometry-used-for-fracture-toughness-measurement.png)
The value of $K$ that causes the notch to grow and cause fractures.
This is value is known as the fracture toughness, $K_c$.
At low thicknesses fracture toughness depends on thickness but as thickness increases, $K_c$
decreases to the constant value, the plane strain fracture toughness, $K_{1c}$.