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---
author: Akbar Rahman
date: \today
title: MMME2051 // Diodes and Rectifiers
tags: [ diodes, rectifier ]
uuid: 21cf8e5b-d808-412c-bb71-d298cdb02b4f
lecture_slides: [ ./lecture_slides/MMME2051EMD_Lecture8.pdf ]
lecture_notes: []
exercise_sheets: []
---
Diodes are like one way valves for electricity --- they allow current to flow in the forward
direction but not in the reverse.
Pure semiconductors are often intentionally doped by specific impurity to alter
its electrical properties.
The most basic thing you can produce with this is the PN junction (or, a diode):
![A PN Junction (diode) with its circuit symbol.](./images/vimscrot-2023-03-23T12:04:26,471475256+00:00.png)
![Real diode behaviour in orange, ideal in red.](./images/vimscrot-2023-03-23T12:06:05,423779641+00:00.png)
- $I_\text{leak}$ is the current that is able to flow in the reverse direction.
It is a very small amount.
- Forward voltage, $V_f$, is the voltage required to move current forward.
- Forward bias impedance, $Z_f$, shows that the diode has a low resistance until a certain point.
- At a certain point a diode will fail to block the reverse voltage (DC blocking voltage)
![A real diode can be approximated with this this of ideal components.](./images/vimscrot-2023-03-23T12:09:18,426229668+00:00.png)
# Rectification
![ElectroBOOM <3](./images/full_bridge_rectifier.gif)
How the rectifiers work are stepped through in lecture slides (pp. 32-44)
The most basic rectification is very wasteful:
![](./images/vimscrot-2023-03-23T12:12:41,250590501+00:00.png)
This produces a waveform like this:
![](./images/vimscrot-2023-03-23T12:13:04,564941427+00:00.png)
This is a step in the right direction but it is still very wasteful and not a smooth
voltage at all.
A H-Bridge (full bridge) rectifier allows the negative cycle to be harnessed as well:
![H-Bridge Rectifier](./images/vimscrot-2023-03-23T12:14:18,334219094+00:00.png)
This produces a voltage like:
![](./images/vimscrot-2023-03-23T12:15:03,479660034+00:00.png)
Capacitors can be added to smooth out the voltage:
![H-Bridge Rectifier with capactior](./images/vimscrot-2023-03-23T12:15:29,203766582+00:00.png)
This produces a voltage like:
![](./images/vimscrot-2023-03-23T12:16:11,795530248+00:00.png)

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---
author: Akbar Rahman
date: \today
title: MMME2051 // Transformers
tags: [ transformers, alternating_current, ac ]
uuid: 486f441f-14ec-41e5-94f9-06f25c534086
lecture_slides: [ ./lecture_slides/MMME2051EMD_Lecture8.pdf ]
exercise_sheets: [ ./exercise_sheets/Exercise Sheet 11 - Transformers.pdf ]
---
Transformers are used to convert between AC voltages.
Transmission is always done at very high voltage to reduce copper losses (heat loss, $E = i^2R$).
![](./images/how.png)
A current carrying coil induces a magnet inside the core.
Another coil is wrapped around the core.
This coil has a current induced in it by induced magnetic field.
![](./images/vimscrot-2023-03-23T11:15:40,310863581+00:00.png)
$$\frac{i_s}{i_p} = \frac{v_p}{v_s} = \frac{n_p}{n_s} = \text{turns ratio}$$
**Note that the current fraction is s over p, not p over s like the others.**
Transformers have very high efficiency so will not be considered for this module and
has been left out of the equation above.
Derivation in lecture slides (pp. 12-15).
Transformers are usually described as having a ratio $p:s$, where $p$ is the number of primary coils
and $s$ the number of secondary coils.
![Symbol of an "Isolaton Tranformer". The dot indicates polarity.](./images/vimscrot-2023-03-23T11:17:40,931099514+00:00.png)
## Referred Impedance
$$\frac{Z_P}{Z_S} = \left(\frac{n_p}{n_s}\right)^2$$
Derivation in in lecture slides (pp. 19-21).